Tag Archives: 25 MSC

VYP Launches 25 Math Short Cuts Book

In celebration of MSC’s 25th foundation day, Virgilio “Ike”Prudente , President of VYP MSC Institute of Technology, is launching his book, 25 Math Short Cuts.

25 Math Short Cuts is a compilation of the short cuts published in our 25 MSC newsletter. Those shortcuts will show that most calculations can be done mentally.

The foreword was written by former Economic Planning Secretary and Director-General Cielito Habito, PhD.

The book has received testimonials from several academic and public personalities, including:

  • Michael Tan, PhD, Chancellor of the University of the Philippines, Diliman
  • Malou Orijola, Assistant Secretary of Department of Science and Technology and Governor, National Book Development Board
  • Rey Vea, President, Mapua Institute of Technology
  • Gen. Hermogenes Esperon, former Chief of Staf, Armed Forces of the Philippines
  • Admiral Ferdinand Golez, Former Flag Officer In Command, Philippine Navy
  • Kenneth Williams, Author of more than 20 Books in Vedic Math
  • Bobby Castro, Chief Operating Officer, Palawan Pawnshop
  • Isaac Pitcairn Yap, former Dean, College of Engineering, Architecture and Technology, Palawan State University
  • Rex Aurelius Robielos, Dean of the School of Industrial Engineering and Engineering Management, Mapua Institute of Technology
  • Emmanuel Nadela, former Chairman, Mechanical Engineering Department, Cebu Institute of Technology
  • Romeo Fule, Math Supervisor, Department of  Education, San Pablo City
  • Albert Saul, Principal, San Pablo Science High School

Many children nowadays avoid Math. Some even hate Math. With this book, Sir Ike hopes to turn those Math Haters into Math Lovers.

You can purchase the book for you or your children, and it is a perfect gift this Christmas.

Contact Virgilio Prudente or the MATH-Inic/MSC office for your orders.

 

25 MSC book cover

25 MSC book cover

MSC 19: Base Multiplication: One Number Above and One Number Below the Base

When one number is above and the other number is below the base, we either

  • a) add the excess of the number above the base to the other number or
  • b) deduct the deficiency of the number below the base from the other number.

Example 19.1:     Find 104 x 98
Our base is 100, 104 is 4 above the base, and 98 is 2 below the base.
104 x 98
= (100 + 4) *(100 – 2)
= (104 – 2) * 100 + 4 *(-2)

Note that 104 – 2 and 98 + 4 will both yield 102
= 10,200 – 08
= 10,192

Example 19.2:     Find 102 x 93
102 x 93
= (100 + 2)(100 – 7)
= 93 + 2 | 2 * (-7) Easier than 102 – 7
= 95 | -14
= 9500 – 14
= 9,486

Example 19.3:     Find 109 x 97
109 x 92
= 109 – 3 | 9*(-3)
= 106 | -27
= 10,573

Here we just deducted 1 from 106 (109 – 3) and affixed the ten’s complement of 27 = (9 x 3) at the end.

Example 19.4:     Find 114 x 88
114 x 88
= (100 + 14) (100 – 12)
= 114 – 12 | 14(-12)
= 102 | -168
= 100 | 200 – 168
= 10,032

Here the right hand part is -168, so we deducted 2 from the left hand part.

Proof:

Let x = base; a, b = excess / deficiency from the base

(x + a)(x – b)
= x2 + (a – b)x + a(-b)
= (x + a – b)x – ab
= [(x + a) – b]x – ab
or
= [(x – b) + a]x – ab

Exercise 19: Find the following products using the base method

  1. ) 12 x 9 =
  2. ) 103 x 98 =
  3. ) 102 x 97 =
  4. ) 102 x 98 =
  5. ) 103 x 97 =
  6. ) 105 x 93 =
  7. ) 75 x 103 =
  8. ) 112 x 89 =
  9. ) 1012 x 991 =
  10. ) 1125 x 995 =

Answers to all exercises are found in the answer key.

Discover the 25 Math Short Cuts ( 25 MSC )!

25th MSC Founding Anniversary Celebration – Schedule and Updates

It’s the MSC 25th Foundation Anniversary Celebration Week!
What’s happening this week?

December 4, 2014  (Thursday)

  • Formal opening of the celebration of MSC’s 25th anniversary
  • Starts with a mass at 8:00 am at the green school campus, followed by a motorcade
  • Opening of the exhibits
  • Inter-class contests (afternoon)
  • Free entrance/scholarship exam for incoming Grade VII students (3:00 pm)
  • At 4:00 pm, Sir Ike’s book, “25 Math Short Cuts” will be launched. Teachers, Principals, Dep Ed officials and friends are expected to grace the event.
25 MSC book cover

25 MSC book cover

December 5, 2014  (Friday)

  • Continuation of open house/exhibits
  • Inter-school contests:

9:00 am – Math-Sci Quiz Show
1:00 pm – Web Design Contest
3:00 pm – Speed Math Contest

interschool events

interschool events

December 6, 2014  (Saturday)

  • MSC Alumni Basketball League (8:00 AM @ Teomora covered court)

8:00 am – Red Team vs White Team

alumni basketball 2
alumni basketball 3
alumni basketball 4
alumni basketball 5
alumni basketball 1
  • Family Day (starting at 8:00 am)
  • PTA raffle/game/boodle fight
  • Sayawit
  • Alumni Homecoming/Awarding of Most Outstanding Alumni (6:00 pm)
MSC Alumni Homecoming 2014

MSC Alumni Homecoming 2014

MSC Music Video Contest

Everyone is invited to join the first ever MSC Christmas Music Video Contest.  Join now and get a chance to win the 5,000 peso-grand prize!

Music video contest

Music video contest

Sing your favorite Christmas song and send us your original video!
Participants:

  • Individual or group
  • No age limit

Song choice:

  • Christmas O.P.M. (Original Pilipino Music)
  • Christmas Classics e.g. Holy Night
  • No spoof songs please!

Video must be:

  • Unique and original (performed by contestant)
  • Submitted as MP4 file

Voting:

  • Christmas music videos will be uploaded to our YouTube channel
  • Promote your entry via Facebook
  • The entry with the most number of views by December 5, 2014, 11:55 PM will be declared as GRAND WINNER.

For details, contact us at 049 562 6006 / 0922 854 3244 / 0939 939 9702 or 0917 853 5069.

MSC Shirt Design Contest

Congratulations to the MSC Shirt Design Contest winners!  Their designs will be used for the coming Alumni Homecoming.

 

shirt design winners

shirt design winners

Call or text these numbers to place your orders: 0922 854 3244 / 0939 939 9702 / 0917 853 5069.

Each shirt costs P200.  Make sure to indicate the shirt design you want and your size (S, M, L, XL).

Related Articles

 

 

 

MSC 18: Base Multiplication – Numbers Below the Base

When multiplying numbers below a power of 10, we subtract one number’s deficiency from the base from the other number and then add the product of the deficiencies.

 Example 18.1:    Find 98 x 97
 = (100 – 2)(100 – 3)
= (100 – 2 – 3)(100) + (-2 x -3)
= (98 – 3) x 100 + 2 * 3
= 95 | 06
 = 9,506

Remember that the right hand side has the same number of digits as the number of zeroes in the base.

Example 18.2:    Find 89 x 87

89 x 87
= (100 – 11)(100 – 13)
= 87 – 11 | 13 * 11 
= 76 | 143
= 77 | 43

It is good practice to use the smaller deficiency as the subtrahend.

Example 18.3:    Find 6,879 x 9,998

6,879 x 9,998
 = 6,879 – 2 | 3,121 * 2
 = 6,877 | 6242
 = 68,776,242

It is definitely easier to subtract 2 from 6,879 than to deduct 3,121 from 9,998.

Here is the algebraic proof of the method used:

Let x = base; a, b = deficiency from the base

(x – a)(x – b)
 = x2 – (a + b)x + a*b
 = (x – a – b)x + a*b
 =[(x – a) – b]x + a*b

 Exercise 18:      Find the following products using the base method.

  1. 6 x 9 =
  2. 99 x 98 =
  3. 98 x 93 =
  4. 88 x 98 =
  5. 75 x 97 =
  6. 87 x 88 =
  7. 97 x 67 =
  8. 94 x 91 =
  9. 995 x 975 =
  10. 997 x 778 =

Answers to all exercises are found in the answer key.

Discover the 25 Math Short Cuts ( 25 MSC )!

MSC 17 – Base Multiplication: Multiplying “Teen” Numbers and Others

Most of us have learned by heart the multiplication table up to 10 x 10. A simple technique will enable us to extend our multiplication power up to 20 x 20.

Example 17.1:     Compute 14 x 12

  • Cover one of the ten’s digit and add what remains to the other number: 14 + 2 or 4 + 12 will both give 16. This will be the first or left hand part of the product.
  • Cover both ten’s digit and multiply what remains: 2 x 4 = 8. This will be the second or right hand part of the answer.
  • Thus 14 x 12 = 16 | 8 or 168
 What we actually did in the first step is to add the excess over the base (10) of a number to the other.In the second step we multiplied the excesses. The algebraic proof of this method, known as base multiplication, is shown below:
(x + a) * (x + b)
= x2 + (a + b) * x + a * b
= (x + a + b) * x + a * b
= [ (x + a) + b] * x + a * b

In our example above, x = 10, a = 4 and b = 2. So we have
14 x 12
= [  (10 + 4) + 2 ] * 10 + 4 * 2
= 160 + 8
= 168   

In this case both multiplicands are above the base.

Example 17.2:     Compute 16 x 13

(10 + 6) x (10 + 3)

  • Add 3 (excess of 13 over 10) to 16 to get 19
    = ( 10 + 6) + 3 |
    = 19 |
  • Multiply the excesses 6 x 3 = 18.
    = 19 | 6 x 3
    = 19 | 18
  • Since there is only one zero in the base, only one place is allotted for the right hand part. Therefore the 1 of 18 must be carried or added to 19 to get a final answer of 208
    = 20 | 8 = 208

Example 17.3:     Find 107 x 104

  • The left part is 107 + 4 = 111, and the right part is 7 * 4 = 28
    (100 + 7) * (100 + 4)
    = 107 + 4 | 7 x 4
    = 111 | 28

= 11,128Note that in this example we did not write the two zeroes after 111 but two places are reserved for the 28.

Example 17.4:     Find 1,025 x 1,012

  • The left part is (1025 + 12 ) = 1037 and the right part is 25 * 12 = 300
    1,025 x 1,012
    = (1000 + 25) * (1000 + 12)
    = 1025 + 12 | 25 * 12
     = 1037 | 300
     = 1,037,300

Example 17.5:     Find 115 x 111

  • The left part is (115 + 11) and the right part 165
    115 x 111
    = (100 + 15) (100 + 11)
    = 115 + 11 | 15 * 11
    = 126 | 165
  • Since we have only two zeroes in our base, we can allot only two spaces for the right hand part of the answer, so we must “carry” the 1 of 165 into the left side.
    = 12,765

Example 17.6:     Find 102 x 104

  • This is pretty straightforward with the left 102 + 4 = 106 and the right is 2 * 4 = 8
    102 * 104
    = (100 + 2) (100 + 4)
    = 102 + 4 | 2(4)
    = 106 | 08
  • In this case, the product of the excesses is 8 but since the base is 100, two spaces are allotted to it. We write it as 08.
    = 10,608

Example 17.7:     103 x 119

  • The left side is 103 + 19 = 3 + 119 = 122 and the right side is 3 * 19 = 57
    (100 + 3) * (100 + 19)
    = 119 + 3 | 3 * 19
    = 12,257
  • Note that in this example we chose to add the smaller excess to the other number. This always leads to a simpler calculation.

Exercise 17: Find the following products using base multiplication

  1. 12 x 13 =
  2. 14 x 17 =
  3. 15 x 18 =
  4. 108 x 101=
  5. 116 x 102 =
  6. 108 x 112 =
  7. 112 x 114=
  8. 123 x 106 =
  9. 1021 x 1006 =
  10. 1432 x 1002 =

Answers to all exercises are found in the answer key.

Discover the 25 Math Short Cuts ( 25 MSC )!

 

 

Conversion: Feet and inches to Meters

Filipinos (and most Americans) are more accustomed to using Feet and Inches in measuring their heights.But the Philippines is officially on the metric system, so we are often required to give our heights in meters or centimeters. It is not difficult to approximate if we remember the following:

  • 100 centimeters = 1 meter
  • I foot = 30 centimeters (cm)
  • 1 inch = 2.5 cm
  • 4 inches = 10 cm

So how do we compute 4’ 8”? How about 5′ 6″?  6′ 11?

Hence, we compute 4′ 8″ as four feet ( 4 x 30cm ) and eight inches ( or 2 x 4 inches, or 2 x 10cm )

  • 4′ 8″
    = 4’ + (2 x 4)” = (4 x 30) + (2 x 10)
    = 120 + 20 = 140 cm = 1.4 m
  • 5’ 6”
    = 5’ + 4” + 2” = (5 x 30) + (1 x 10) + (2 x 2.5)
    = 150 + 10 + 5 = 165 cm = 1.65 m
  • 6’11”
    =  6’ + (2×4”) + (3 x1”) = (6 x 30) + (2 x 10) + (3 x 2.5)
    = 180 +20 + 7.5 = 207.5m

Note that under this conversion 6’ 8” is 2.0 m

We used 2,5 cm = 1 inch instead of the exact 2.54 cm = 1 inch. To make our conversion more accurate we can add 0.5 cm for every  foot

So more accurately, we estimate as follows:

  • 4’ 8”
    = 4’ + (2 x 4)” (4 x 30) + 4 x 0.5+ (2 x 10)
    = 120 + 2 + 20 = 142 cm = 1.42 m
  • 5’ 6”
    = 5’ + 4” + 2” = (5 x 30) + (5 x 0.5)+ (1 x 10) + (2 x 2.5)
    = 150 + 2.5 + 10 + 5 = 167.5 cm = 1.675 m
  • 6’ 11”
    =  6’ + (2×4”) + (3 x1”) = (6 x 30) + (6 x 0.5)+(2 x 10) + (3 x 2.5)
    = 180 + 3+20 + 7.5 = 210.5cm

A easier and more accurate way to compute the last example is to treat 6′ 11″ as 7 feet less 1 inch

  • 7′  minus 1″
    = (7’ x 30) + (7 x 0.5) – 2.5
    = 210 + 3.5 – 2.5 = 211 cm = 2.11m

Feet and inches to meters made easy!

 

MSC’s 25th FOUNDATION CELEBRATION ACTIVITIES

We’re just about there!

We will celebrate the 25th Anniversary of VYP-MSC Institute of Technology with a week long series of activities, culminating with the MSC Alumni Homecoming and Awarding Ceremonies for the MSC Outstanding Alumni.

 

Date Time Event
November 8
November 15
November 29		  7:00 am MSC Alumni Basketball League games (at Teomora covered court)
December 1 Campus Clean up drive (MSC students and staff)
December 3 Ingress of Exhibits
December  3 Book Launch “25 Math Shortcuts”
December 4 – 6 Open House and Exhibits
December 4  8:00 am Mass, Motorcade, Opening of Exhibits
December 4  1:00 pm Scavenger Hunt (for elementary schools/for MSC Students)
December 4  3:00 pm Free Entrance/Scholarship Exam (for graduating elem. school pupils)
December 4  3:00 pm MSC High School Got Talent, Mr. and Ms. MSC
December 5  9:00 am 13th Inter-elementary School Math-Sci Quiz Show
December 5  1:00 pm 5th MATH Made So Cool Speed Math Contest
December 5  3:00 pm 9th Inter- School Web Design Contest
December 6  7:00 am MSC Alumni Basketball League Championship (at Teomora covered court)
December 6  8:00 am Family Day
December 6  3:00 pm Sayawit
December 6  4:00 pm MSC Alumni Homecoming and Awarding of MSC’s Most Outstanding Alumni

*All activities shall be held at the green school campus of MSC at San Gabriel, San Pablo City, except for the basketball games.

MSC 16 – Multiplying Complementary Numbers

Complementary numbers are numbers with the same initial digits and the sum of the last digits equal to 10.

The technique in multiplying complementary numbers is similar to that of squaring numbers ending in 5 (By one more than the one before) except that the right hand part is not 25 but the product of the last digits

Example 16.1:    Find 46 x 44

             =  4 x 5 | 6 x 4

             = 20 | 24

              = 2,024

P16: Let t = the common ten’s digit; a, b = the units digit such that a + b = 10

(10t + a)(10t + b)

= (10t)(10t) + 10ta + 10tb + ab

= 100t2 + 10t(a + b) + ab

= 100t2 + 10t(10) + ab

= 100(t2 + t)+ ab

= 100 t(t + 1)+ ab

 

Example 16.2:    Find 39 x 31

= 3 x 4 | 9 x 1

= 12|09 Note that the right part has two digits, 09 not 9.

= 1,209

Again, this can be applied to decimals and fractions as long as they have the same whole number part and their decimal and fractional parts total to 1.

Example 16.3:    8.3 x 8.7 = 8 x 9 | .3 x .7 = 72.21

Example 16.4:    4  2/7 x 4  5/7 = 4 x 5 | 2/7 x  5/7 = 20 10/49

Example 16.5:    699 x 601

Since 99 + 01 = 100, we can also apply complimentary rule

699 x 601 = 6 x 7 | 99 x 01 = 42| 0099 = 420,099

 Exercise 16:

  1. ) 24 x 26 =
  2. ) 73 x77 =
  3. ) 81 x 89 =
  4. ) 998 x 992 =
  5. ) 4.3 x 4.7 =
  6. ) 7.4 x 7.6 =
  7. ) 3 3/7 x 3 4/7 =
  8. ) 4 1/6 x 4 5/6 =
  9. ) 2 4/9 x 2 5/9 =
  10. ) 297 x 203 =

Answers to all exercises are found in the answer key.

Discover the 25 Math Short Cuts ( 25 MSC )!